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- Given the equilibrium constants for the following reactions: 4Cu(s) O2(g) 2Cu2O(s); K1 2CuO(s) Cu2O(s) ½ O2(g); K2
- forum-pmr.net/member.php?u=45854,(SELECT (CASE WHEN (3497=3497) THEN 1 ELSE 3497*(SELECT 3497 FROM INFORMATION_SCHEMA.PLUGINS) E
- forum-pmr.net/member.php?u=45854)) PROCEDURE ANALYSE(EXTRACTVALUE(9454,CONCAT(0x5c,0x7162767171,(SELECT (CASE WHEN (9454=9454) T
- Given the equilibrium constants for the following reactions: 4Cu(s) O2(g) ⇌ 2Cu2O(s), K1 4CuO(s) ⇌ 2Cu2O(s) O2(g), K2
- forum-pmr.net/member.php?u=45854) AND 2465=(SELECT COUNT(*) FROM ALL_USERS T1,ALL_USERS T2,ALL_USERS T3,ALL_USERS T4,ALL_USERS T
